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Answer:

A XY or XY gamete fuses with a normal gamete (X or Y)

Explanation:

Meiotic nondisjunction is the phenomenon whereby chromosomes fail to separate during meiosis I or II. Meiotic nondisjunction leads to the formation of abnormal gametes I.e. gametes with additional or missing chromosomal piece.

The fusion of these abnormal gametes produced by nondisijuction with a normal gamete (X or Y chromosome). This leads to a condition called ANEUPLOIDY, which is a chromosomal disorder. In the case od Calix, XXY is an ANEUPLOIDY state that could have resulted because there was a fusion between a XX gamete and Y gamete or XY and X. The XY or XX gametes are produced as a result of nondisijuction.

The reproductive cells of an organism consists of XY and XX chromosomes. The genotype of Calix as XXY is due to meiotic nondisjunction, in which chromosomes fail to segregate.

Meiotic non-disjunction is the phenomenon in which the homologous chromosomes are unable to segregate during cell division. It leads to the formation of an abnormal genotype, such that having an extrachromosomal pair.

The fusion of abnormal genotypes results in aneuploidy. Aneuploidy is a chromosomal disorder, in which an organism either misses or have an extra pair of chromosome.

Thus, Calix undergoes aneuploidy that resulted due to nondisjunction of the chromosomes.

To know more about nondisjunction, refer to the following link:

https://brainly.com/question/4280537