Answer:
There will be 3472 cats in 10 years
Step-by-step explanation:
There were 3500 cats
The number of dogs in a city is declining at a rate of about 0.08% each year.
We are supposed to find the no. of cats in 10 years
Formula :[tex]N(t)=N_0(1-r)^t[/tex]
Where N(t) = Remaining cats after t days
[tex]N_0[/tex] = Initial population
r = rate of depreciation
t=time
So, No. of cats remained after 10 years = [tex]3500(1-\frac{0.08}{100})^{10}=3472.100[/tex]
Hence There will be 3472 cats in 10 years
