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In trapezoid $WXYZ$, $\overline{XY} \parallel \overline{WZ}$, $\angle WXZ = 105^\circ$, $\angle W = 43^\circ$, and $\angle Y = 141^\circ$. Find $\angle YXZ$, in degrees.

Respuesta :

Answer:

32 degrees

Step-by-step explanation:

The diagram of the problem is drawn and attached.

In Triangle WXZ

105+43+[tex]\angle WZX[/tex]=180 (Sum of Angles in a Triangle)

148+[tex]\angle WZX[/tex]=180

[tex]\angle WZX[/tex]=180-148

[tex]\angle WZX[/tex]=32 degrees

Since |XY|//|WZ| (parallel to)

[tex]\angle WZX[/tex]=[tex]\angle YXZ[/tex] (Alternate Angles)

Therefore:

[tex]\angle YXZ[/tex]=32 degrees

Ver imagen Newton9022

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