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A ball is dropped from rest from a Cliff and falls for 3 seconds.
Neglecting air resistance, the final velocity of the ball is
m/s. (g = -9.8 m/s2)
Enter the answer

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MathPhys

Answer:

-29.4 m/s

Explanation:

Given:

v₀ = 0 m/s

t = 3 s

a = -9.8 m/s²

Find: v

v = at + v₀

v = (-9.8 m/s²) (3 s) + (0 m/s)

v = -29.4 m/s

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