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Justin added concentrated HCl solution in excess to 45.8 grams of magnesium metal and collected the hydrogen gas that was produced by the reaction.

Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)

If Justin collected 2.01 grams of H2, what was the percent yield of H2?
A 4.39%
B 46.9%
C 52.9%
D 93.8%

Respuesta :

Halberd

Answer:

Explanation:

I have the same question

Answer:

52.9 %.

Explanation:

Mg + 2HCl ---> MgCl2 + H2

Using the relative atomic masses of magnesium and hydrogen:

Theoretically 24.3 g of Mg will produce 2.016 g of H2

so 45.8 g will produce (2.016 * 45.8) / 24.3 = 3.80 g H2.

So the % yield = 2.01 * 100 / 3.80

= 52.9%.