Answer:
3.42g
Explanation:
Molar mass of sugar ([tex]C_{12}H_{22}O_{11}[/tex]) is = 12x12 + 22x1 + 16x11 = 144 + 22 + 176
= 342g/Mol
To weight required for 0.100M = 342 x 0.1 = 34.2g/Liter
To prepare glass of Kool-aid (0.1L) required weight = 34.2 x 0.1 = 3.42g
