Answer: 0.28 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock [tex]LiOH[/tex] solution = 4.5 ml
[tex]V_1[/tex] = volume of stock [tex]LiOH[/tex] solution = 27 ml
[tex]M_2[/tex] = molarity of dilute c solution = ?
[tex]V_2[/tex] = volume of dilute [tex]LiOH[/tex] solution = 435 ml
[tex]4.5\times 27=M_2\times 435[/tex]
[tex]M_2=0.28M[/tex]
Thus the concentration of LiOH be if 27 ml of a 4.5 M LiOH solution is diluted to 435 ml is 0.28 M
