Respuesta :
Answer:
0.625 kg
Explanation:
Since 90.6 is 3 half-lives from 30.2 (90.6/30.2 = 3) , divide the initial mass of the sample by 2, and divide that quotient by 2, and divide THAT quotient by 2 to determine how much remains after 3 half-lives.
The mass will remain at 1.6 kg.
How to find the mass after 90.6 years?
Mass after t years:
The mass of the elements after t years is given by the following equation:
M(t) = M(0)(1-r)[tex]^{t}[/tex]
The half-life of Cs-137 is 30.2 years.
This means that:
M (30.2) = 0.5 M (0)
M (t) = M (0)(0.9773)[tex]^{t}[/tex]
If the initial mass of the sample is 5 kg, how much will remain after 90.6 years?
This is M(151), with M(0) = 100.
Then,
M(90.6) = 5(0.9773)[tex]^{90.6}[/tex]
= 5*0.24
= 1.2 kg
Cesium-137 emits beta particles as it decays to the barium isotope, Ba-137m.
Learn more about initial mass here: brainly.com/question/25573309
#SPJ2