Answer:
A. 4500 mL
Explanation:
We need to use a version of the combined gas law, which states:
[tex]\frac{V_1}{n_1T_1}= \frac{V_2}{n_2T_2}[/tex] , where T represents temperature, V volume, and n moles
First, look at the initial values of n, V, and T:
- n: we have 10.0 grams of hydrogen, which we need to convert to moles. So: [tex]10.0g*\frac{1 mol}{2.02 g} =4.95molH_2[/tex]
- V: we have a volume of 5.0 L
- T: our temperature right now is 28.0°C, but we need it in Kelvins, so add 273: 28.0 + 273 = 301 K
Now look at the final values:
- n: our final number of grams is 8.5 grams of hydrogen, so we need to convert this to moles.
[tex]8.5g*\frac{1 mol}{2.02 g} =4.2molH_2[/tex]
- V: this is what we want to find
- T: our final temperature is 44.0°C; to convert it to Kelvins, add 273.
44.0 + 273 = 317 K
Put this altogether:
[tex]\frac{V_1}{n_1T_1}= \frac{V_2}{n_2T_2}[/tex]
[tex]\frac{5.0}{4.95*301}= \frac{V_2}{4.2*317}[/tex]
Multiply both sides by (4.2 * 317):
[tex]V_2[/tex] ≈ 4.5 L
However, the problem wants millilitres, so simply multiply 4.5 by 1000:
4.5 * 1000 = 4500
The answer is thus A.
