Step-by-step explanation:
It is given that,
The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. So, radius of tennis ball is 1 cm and radius of softball is 0.5 cm.
Both balls are in the shape of sphere. Half of the balls will becomes hemisphere. The surface area of hemisphere is given by :
[tex]A=2\pi r^2[/tex]
Taking ratio of both balls, i.e.
[tex]\dfrac{A_1}{A_2}=\dfrac{r_1^2}{r_2^2}[/tex]
[tex]\dfrac{A_t}{A_s}=\dfrac{r_t^2}{r_s^2}\\\\\dfrac{A_t}{A_s}=\dfrac{1^2}{(0.5)^2}\\\\\dfrac{A_t}{A_s}=4[/tex]
So, the surface area of a half of the tennis ball is 4 times of he surface area of a half of the softball.
