Answer:
A
Explanation:
To answer this, we need to use Gay-Lussac's law, which states that:
[tex]\frac{P_1}{T_1}= \frac{P_2}{T_2}[/tex] , where P is pressure and T is temperature
The initial pressure we're given is 4.5 atm (so P1 = 4.5) and the temperature is 45.0°C; however, we need to change Celsius to Kelvins, so add 273 to 45.0: 45.0 + 273 = 318 K (so T1 = 318).
The final pressure is what we want to find, but we do know the final temperature is 3.1°C. Converting this to Kelvins, we get: 3.1 + 273 = 276.1 K, which means T2 = 276.1.
Plug these values in:
[tex]\frac{P_1}{T_1}= \frac{P_2}{T_2}[/tex]
[tex]\frac{4.5}{318}= \frac{P_2}{276.1}[/tex]
Multiply both sides by 276.1:
[tex]P_2[/tex] ≈ 3.9 atm
The answer is thus A.
