Answer:
The probability of getting a nickel, then a dime is 2/21
Step-by-step explanation:
No. of pennies = 9
No. of nickels = 10
No. of dimes = 12
No. of quarters = 5
Total items = 9+10+12+5=36
So, Probability of getting nickel on first draw = [tex]\frac{10}{36}[/tex]
Now the nickle in not replaced
So, Total items = 36-1 = 35
So, Probability of getting dime on second draw =[tex]\frac{12}{35}[/tex]
So, the probability of getting a nickel, then a dime = [tex]\frac{10}{36} \times \frac{12}{35}=\frac{2}{21}[/tex]
Hence the probability of getting a nickel, then a dime is 2/21
