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ight energy can be described as nhf , where n is a number of photons, h is Planck's constant, and f is the frequency of the light, also denoted by the symbol ???? . Calculate the minimum number of photons, n , needed to make the reduction of 2 moles of NADP+ favorable for light absorbed at 680.000 nm . Assume that the amount of energy needed for the reduction of one mole of NADP+ to be favorable must exceed 219 kJ/mol .

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tutorAnne

Answer:

1.496x 10^24photons

Explanation:

wavelength λ= 680 X10^-9 nm

h = planks constant - 6.636*10 ^-34js

c- speed of light - 3.0x 10^8 m/s

I mole of  Energy of NADP+ = 219Kj/mol

2 moles of  Energy of NADP+ = 2x 219= 438kj/mol = 438x10^3j

/mol

E= nhc/λ

438x 10^3j/mol -= n x (6.636*10 ^-34 x  3x10^8) / 680*10^-9

n=438x10^3j x 680x 10^-9/ (6.636*10 ^-34 x 3.0x10^8

1.496x 10^24photons

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