A spring is laid horizontally on a table and a force of 62 N is required to stretch the spring 12 cm. The spring is then held vertically and an object is attached to the end of it which causes the spring to stretch 9.7 cm. What is the Mass of the object?
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Where x is the displacement of the spring’s end from its equilibrium position, F is the force applied to the spring, k is a constant known as spring constant.

At first a force (F) of 62 N i used to stretch a spring by 12 cm (x).

Substituting into Hooke's equation:

F = kx

k = F/x = 62 / 12 = 5.17 N/cm

The spring is then held vertically and an object. The object is acted by upon by acceleration due to gravity since it is vertically upward. Therefore the force created by the object F = mg where g = acceleration due to gravity = 9.8 m/s². It causes a stretch (x) of 9.7 cm

Therefore:

mg = 5.17 N/cm × 9.7 cm

9.81m = 50.117

m = 50.117 / 9.81 = 5.11 kg

A spring is laid horizontally on a table and a force of 62 N is required to stretch the spring 12 cm. The spring is then held vertically and an object is attached to the end of it which causes the spring to stretch 9.7 cm. What is the Mass of the object? SHOW YOUR WORK

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A spring is laid horizontally on a table and a force of 62 N is required to stretch the spring 12 cm. The spring is then held vertically and an object is attached to the end of it which causes the spring to stretch 9.7 cm. What is the Mass of the object?
SHOW YOUR WORK