Respuesta :
Answer:
The 95.7% confidence interval for the expected amount of garbage per bin for all bins in the city
(48.937 , 50.863)
Step-by-step explanation:
Explanation:-
Given data random sample of 46 bins, the sample mean amount was 49.9 pounds and the sample standard deviation was 3.641
The sample size 'n' =46
mean of the sample x⁻ = 49.9
Standard deviation of the sample S = 3.641
Confidence intervals:-
The 95.7% confidence interval for the expected amount of garbage per bin for all bins in the city
[tex](x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })[/tex]
Degrees of freedom = n-1 = 46-1 =45
The tabulated value t₀.₉₆ = 1.794 ( from t-table)
[tex](49.9 - 1.794 \frac{3.641}{\sqrt{46} } ,49.9+ 1.794 \frac{3.641}{\sqrt{46} })[/tex]
(49.9 -0.9630 , 49.9+0.9630)
(48.937 , 50.863)
Conclusion:-
The 95.7% confidence interval for the expected amount of garbage per bin for all bins in the city
(48.937 , 50.863)
