A red die and a blue die are thrown. Both dice are loaded (that is, not all sides are equally likely). Rolling a 1 with the red die is twice as likely as rolling each of the other five numbers and rolling a 3 with the blue die is twice as likely as rolling each of the other five numbers. a. (2.5 pt.) What is the probability of each outcome of the red die

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Answer:

P(1) = 0.2857

P(2) = 0.1428

P(3) = 0.1428

P(4) = 0.1428

P(5) = 0.1428

P(6) = 0.1428

Step-by-step explanation:

From the question, we know that Rolling a 1 with the red die is twice as likely as rolling each of the other five numbers, so we can write the following equation:

P(1) = 2X        

Where X is the probability of rolling each of the other five numbers or:

P(2) = P(3) = P(4) = P(5) = P(6) = X  

Additionally, the sum of all the probabilities is 1, so:

P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1

Now, we can replace P(1) by 2X and P(2), P(3), P(4), P(5) and P(6) by X, as:

P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1

2X  +   X   +    X   +   X  +   X   +   X  = 1

Finally, solving for X, we get:

7X = 1

X = 1/7

X = 0.1428

So, the probability of rolling a 1 is equal to:

P(1) = 2X  = 2*(0.1428) = 0.2857

And the probability of rolling each of the other five numbers is:

P(2) = P(3) = P(4) = P(5) = P(6) = X  

P(2) = P(3) = P(4) = P(5) = P(6) = 0.1428