Respuesta :
Answer:
[tex]z=\frac{0.565 -0.58}{\sqrt{\frac{0.58(1-0.58)}{600}}}=-0.744[/tex]
Since is a bilateral test the p value would be given by:
[tex]p_v =2*P(z<-0.744)=0.4569[/tex]
And since the p value is higher than the significance level we have enough evidence to conclude that the true proportion is not significantly different from 0.58
Step-by-step explanation:
Information given
n=600 represent the random sample selcted
X=339 represent the number of females aged 15 and older that living alone
[tex]\hat p=\frac{339}{600}=0.565[/tex] estimated proportion of females aged 15 and older that living alone
[tex]p_o=0.58[/tex] is the value that we want to check
[tex]\alpha=0.01[/tex] represent the significance level
z would represent the statistic
[tex]p_[/tex] represent the p value
Sytem of hypothesis
We want to check if the true proportion females aged 15 and older that living alone is significantly different from 0.58.:
Null hypothesis:[tex]p=0.58[/tex]
Alternative hypothesis:[tex]p \neq 0.58[/tex]
The statistic is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
Replacing the info given we got:
[tex]z=\frac{0.565 -0.58}{\sqrt{\frac{0.58(1-0.58)}{600}}}=-0.744[/tex]
Since is a bilateral test the p value would be given by:
[tex]p_v =2*P(z<-0.744)=0.4569[/tex]
And since the p value is higher than the significance level we have enough evidence to conclude that the true proportion is not significantly different from 0.58