Answer:
0.0198 mm/sec
Explanation:
Given:
d = 8 cm
L = 10 m = 1000 cm
v = 200 m/min
E = 100%
density = 3500 A.m^-2
Using Faraday's law of electrolysis, we have:
Q = n(e) * F
Where,
Q = electric charge
F = Faraday's constant=96500Cmol
n(e) = electron charge = 2
Therefore
Q= 96500 * 2 = 193000
Let's find the area of pipe, A = πr²(L)
But radius, r = [tex] \frac{d}{2} = \frac{4}{2} = 4cm [/tex]
Therefore,
A = 3.142 * 4² * 1000
A = 50272
To find the thickness of the coating deposited, we have :
[tex] = \frac{193000 * 7.31 * 118.7 * 200}{96500 * 50272 * 3500} = 1.98 * 10^-^3[/tex]
= 0.0198 mm/sec
