Answer:
see explaination
Step-by-step explanation:
Given a=0.01, the critical value is t(0.01, df=n-1=7) =3 (from student t table)
the critical region is one-sided
the rejection region is t>3
the test statistic value
t= mean difference / std.error
=7.35/4.1866
=1.756
Stating the conclusion in the problem context:
Fail to reject H0. The data does not suggest a significant mean difference in breaking load for the two fabric load conditions.
See attachment for further solution.