Answer:
0.72 M
Explanation:
Given data
- Initial volume of the H₂SO₄ solution (V₁): 200 mL
- Volume of water added (VH₂O): 300 mL
- Initial concentration of the H₂SO₄ solution (C₁): 1.8 M
Step 1: Calculate the final volume (V₂)
The final volume of the solution is equal to the sum of the initial volume of the solution and the volume of water.
[tex]V_2 = V_1 + VH_2O = 200 mL + 300mL = 500mL[/tex]
Step 2: Calculate the concentration of the diluted solution (C₂)
We will use the dilution rule.
[tex]C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{1.8M \times 200mL}{500mL}= 0.72 M[/tex]
