Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.8 parts/million (ppm). A researcher believes that the current ozone level is not at a normal level. The mean of 16 samples is 8.2 ppm with a standard deviation of 0.6. Assume the population is normally distributed. A level of significance of 0.01 will be used. Find the value of the test statistic. Round your answer to two decimal places.

Respuesta :

Answer:

The value of the test statistic is [tex]t = 2.67[/tex]

Step-by-step explanation:

The null hypothesis is:

[tex]H_{0} = 7.8[/tex]

The alternate hypotesis is:

[tex]H_{1} \neq 7.8[/tex]

Our test statistic is:

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

In this problem, we have that:

[tex]X = 8.2, \mu = 7.8, \sigma = 0.6, n = 16[/tex]

Then

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]t = \frac{8.2 - 7.8}{\frac{0.6}{\sqrt{16}}}[/tex]

[tex]t = 2.67[/tex]

The value of the test statistic is [tex]t = 2.67[/tex]