Answer:
Multiply the numerators and the denominators.
Step-by-step explanation:
Problem: [tex]\dfrac{1}{x^2}- \dfrac{2}{y}\div y-2x^2[/tex]
Step 1: [tex]\dfrac{y}{x^2y}- \dfrac{2x^2}{x^2y}\div y-2x^2[/tex]
Step 2: [tex]\dfrac{y-2x^2}{x^2y} \div \dfrac{y-2x^2}{1}[/tex]
Step 3: [tex]\dfrac{y-2x^2}{x^2y} X \dfrac{1}{y-2x^2}[/tex]
The next step would be to multiply the numerators and the denominators.
Step 4: [tex]\dfrac{y-2x^2}{(x^2y)(y-2x^2)}[/tex]
Since [tex]y-2x^2[/tex] is common in the numerator and denominator, it divides itself, thus our result is:
[tex]\dfrac{1}{x^2y}[/tex]
