Answer:
Explanation:
Total time of transfer oil fuel = 2.45 x 9 = 22.05 minutes
= 22.05 x 60
= 1323 s
Total volume of ful transferred = 687 gallon
= .0037854 x 687
= 2.6 m³
radius of pipe = .5 x 1.45 inch
= .5 x 1.45 x 2.54 x 10⁻² m
r = .018415 m
cross sectional area
= π r²
a = 3.14 x .018415²
= 10.648 x 10⁻⁴ m²
If v be the velocity
volume of fuel coming out a x v x t , a is cross sectional area , v is velocity and t is time .
10.648 x 10⁻⁴ x v x 1323 = 2.6
v = 1.845 m / s
This question involves the concepts of volume flow rate, flow speed, and cross-sectional area.
The velocity of fuel through the nozzle is "1.09 m/s".
The flow speed of fuel can be found using the formula for the volume flow rate of fuel:
[tex]\frac{V}{t}=Av\\\\V = Avt\\\\v = \frac{At}{V}[/tex]
where,
v = flow speed = ?
A = cross-sectional area = π(radius)² = π(1.45/2 in)²[tex](\frac{0.0254\ m}{1\ in})^2[/tex] = 0.0022 m²
t = time taken for refueling = (9)(2.45 min) = 22.05 min = 1323 s
V = Volume of fuel transferred = (687 gallons)[tex](\frac{0.003785 \ m^3}{1\ gallon})[/tex] = 2.6 m³
Therefore,
[tex]v=\frac{(0.0022\ m^3)(1323\ s)}{2.6\ m^3}\\\\[/tex]
v = 1.09 m/s
Learn more about volume flow rate here:
https://brainly.com/question/23127034?referrer=searchResults
