Answer:
= 37 g
Explanation:
H₂SO₄ + 2NaOH ----> Na₂SO₄ + 2H₂O
2 moles of NaOH react with 1 mole of H₂SO₄
0.75 moles of NaOH will react with (0.75 / 2)×1
= 0.375 moles of H₂SO₄.
Formular mass of H₂SO₄ = (1×2)+32+(16×4) = 98g
1 mole of H₂SO₄ weighs 98g
0.375 moles of H₂SO₄ will weigh ( 0.375×98)g
= 36.7g = 37g of H₂SO₄
