Answer:
[tex]\frac{2n^2}{5n^2-6n+1}[/tex]
Step-by-step explanation:
The problem is as follows:
[tex]\frac{2n-3}{10n^2-17n+3} *\frac{15n^3-3n^3}{6n^2-6n}[/tex]
To make this problem simpler to solve, you can simplify the fractions. The first fraction can be simplified by factoring the denominator and cancelling out like factors.
[tex]\frac{2n-3}{10n^2-17n+3} \\\frac{2n-3}{(2n-3)(5n-1)} \\\frac{1}{5n-1}[/tex]
The second fraction can be simplified by cancelling out like factors.
[tex]\frac{15n^3-3n^3}{6n^2-6n}\\\frac{12n^3}{6n^2-6n}\\\frac{2n^2}{n-1}[/tex]
Now, you can multiply the two fractions quite easily
[tex]\frac{1}{5n-1} *\frac{2n^2}{n-1}\\\frac{2n^2}{5n^2-6n+1}[/tex]
