The spring is stretched by 0.316 m, when force is exerted.
What is Hooke's law?
If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.
F = kx
where k is the proportionality constant called the spring constant or force constant.
Given, a screen door spring has a spring constant of 188 N/m, and when stretched, a 59.5 N force is applied on the door.
Substitute the values, we get
59.5 = 188 x
x = 0.316 m
Thus, the spring is stretched by 0.316 m, when force is exerted.
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