Answer:
1034.88J
Explanation:
Given that:
mass (m) = 11.2 g, initial temperature = 0°C, final temperature = 22°C, the specific heat capacity of water (C) = 4.2 J/g°C
Temperature difference (ΔT) = final temperature - initial temperature = 22 - 0 = 22°C
The quantity of heat (Q) required to melt the ice can be calculated from the equation:
Q = mCΔT
Q = 11.2 g × 4.2 J/g°C × 22°C
Q = 1034.88J
