Answer:
The frequency the cyclist observes is 1029.412 Hz
Explanation:
Here we have that the frequency is given by the relation;
[tex]f_{obs} = f_{source}\left (\frac{v \pm v_{obs}}{v \pm v_{source}} \right )[/tex]
Where:
[tex]f_{obs}[/tex] = Frequency sensed by the observer
[tex]f_{source}[/tex] = Frequency emitted by the source = 1,000 Hz
v = Velocity of sound in air
[tex]v_{obs}[/tex] = Speed of observer = + 10 m/s
[tex]v_{source}[/tex] = Speed of source = 0 m/s
Plugging in the values, we have;
[tex]f_{obs} =1000 \times \left (\frac{340 + 10}{340 + 0} \right ) = 1000 \times \left (\frac{350}{340 } \right ) = 1029.412 \ Hz[/tex]
Therefore, the frequency the cyclist observes = 1029.412 Hz.
