these are all my points I'm desperate please help I've posted this 4 other times

Answer:
y = (x+3)^2 -1
Step-by-step explanation:
The vertex form of the equation is
y = a(x-h)^2 +k where (h,k) is the vertex
The vertex is (-3,-1)
y = a(x- -3)^2 -1
y = a(x+3)^2 -1
Pick another point (-2,0) and substitute it into the equation
0 = a(-2+3)^2 -1 to find a
0 =a(1)^2 -1
0 = a-1
1 = a
y = (x+3)^2 -1
Answer:
y = (x + 3)² - 1
y = x² + 6x + 8
Step-by-step explanation:
Vertex: (-3,-1)
y-intercept: (0,8)
y = a(x - -3)² - 1
y = a(x + 3)² - 1
8 = a(0 + 3)² - 1
9a = 9
a = 1
y = (x + 3)² - 1
y = x² + 6x + 8