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Write a program that has an array of at least 50 string objects that hold people’s names and phone numbers. The program then reads lines of text from a file named phonebook into the array. The program should ask the user to enter a name or partial name to search for in the array. All entries in the array that match the string entered should be displayed-- thus there may be more than one entry displayed. The program prints the message "Enter a name or partial name to search for: " and then after the user enters some input and hits return, the program skips a line, and prints the heading: "Here are the results of the search:", followed by each matched string in the array on a line by itself. Input Validation: None

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kendrich

Answer:

See explaination

Explanation:

#include <iostream>

#include <fstream>

#include <string>

using namespace std;

int main()

{

const int SIZE = 50;

string phoneDirectory[SIZE];

int size=0;

string name; //name to look for

ifstream inFile;

inFile.open("phonebook");

while (!inFile.fail()) {

getline(inFile,phoneDirectory[size]);

size++;

}

inFile.close();

// Get a name or partial name to search for.

cout << "Enter a name or partial name to search for: ";

getline(cin, name);

cout << "\nHere are the results of the search: " << endl;

int numberEntriesFound = 0;

for (int k = 0; k < size; k++)

{

if (phoneDirectory[k].find(name.data(), 0) < phoneDirectory[k].length())

{

numberEntriesFound ++;

cout << phoneDirectory[k] << endl;

}

}

if (numberEntriesFound == 0)

cout << "\nNo Entries were found for " << name;

return 0;

}

lhmarianateixeira

In this exercise we have to use the knowledge of computational language in C code to write the code.

This code can be found in the attached image.

To make it simpler the code is described as:

#include <iostream>

#include <fstream>

#include <string>

using namespace std;

int main()

{

const int SIZE = 50;

string phoneDirectory[SIZE];

int size=0;

string name;

ifstream inFile;

inFile.open("phonebook");

while (!inFile.fail()) {

getline(inFile,phoneDirectory[size]);

size++;

}

inFile.close();

cout << "Enter a name or partial name to search for: ";

getline(cin, name);

cout << "\nHere are the results of the search: " << endl;

int numberEntriesFound = 0;

for (int k = 0; k < size; k++)

{

if (phoneDirectory[k].find(name.data(), 0) < phoneDirectory[k].length())

{

numberEntriesFound ++;

cout << phoneDirectory[k] << endl;

}

}

if (numberEntriesFound == 0)

cout << "\nNo Entries were found for " << name;

return 0;

}

See more about C code at brainly.com/question/22841107

Ver imagen lhmarianateixeira

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