A spoiler used on race cars to produce a negative lift, thereby providing a better traction. The lift coefficient for the spoiler is 1.1,and the coefficient of friction between the wheels and the pavement is 0.6. If the race car travels with a speed of 200 mph, by how much would the spoiler increase the maximum tractive force that could be produced between the wheels and ground

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Busiyijide Busiyijide · Answer 1 · 2020-05-11T04:04:45+02:00

Answer:

405 Ib

Explanation:

the picture below shows the explanation to the problem. Its so explanatory and i hope it helps you

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Chrisnando Chrisnando · Answer 2 · 2020-05-11T04:10:18+02:00

Image to question is attached.

Answer:

f₂ = 405 lb

Explanation:

Given:

Coefficient of friction, u = 0.6

Lift coefficient for spoiler, c= 1.1

Speed, V = 200 mph => convert to ft/s, we have:

[tex] 200mi/hr * 5280mi * \frac{1hr}{3600s} = 293.3ft/s [/tex]

To find the new tractive force, we have:

f₂ = u*N₂ = uL

Where L = ½ PV²*c*A

[tex]f_2 = 0.6 * \frac{1}{2} * 0.00238 * 293.3^2 * 1.1 * 1.5 * 4 = 405 lb [/tex]

The maximum tractive force that could be produced between the wheels and ground would be increased by 405 lb.