Greg throws a 2.8-kg pumpkin horizontally off the top of the school roof in order to hit Mr. H's car. The car has parked a distance of 13.4 m away from the base of the building below the point where Greg is standing. The building's roof is 10.4 m high. Assuming no air resistance, with what horizontal speed does Greg toss the pumpkin in order to hit Mr. H's car

Respuesta :

Answer:

The horizontal velocity is [tex]v = 9.2 m/s[/tex]

Explanation:

From the question we are told that

     The mass of the pumpkin is  [tex]m = 2.8 \ kg[/tex]

      The distance of the the car from the building's base is  [tex]d = 13.4 \ m[/tex]

       The height of the roof is [tex]h = 10.4 \ m[/tex]

       

The height is mathematically represented as

         [tex]h = \frac{1}{2} gt^2[/tex]

Where g is the acceleration due to gravity which has a value of [tex]g =9.8 \ m/s^2[/tex]

substituting values

          [tex]10.4= 0.5 * 9.8 * t[/tex]

making the time taken the subject of the formula

         [tex]t = \frac{10.4}{0.5 * 9.8 }[/tex]

          [tex]t = 1.457 \ s[/tex]

The speed at which the pumpkin move horizontally can be represented mathematically  as

                         [tex]v = \frac{d}{t}[/tex]

substituting values

                     [tex]v =\frac{13.4}{1.457}[/tex]

                     [tex]v = 9.2 m/s[/tex]