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Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (568 nm) on a double slit with a separation of 0.105 mm. The diffraction pattern shines on the classroom wall 3.5 m away. Calculate the fringe separation between the fourth order and central fringe.

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Rau7star

Answer:

19mm

Explanation:

Given:

wavelength λ= 568nm

L= 3.5m

distance between the slits 'd' = 0.105mm

Fringe width can be determined by the formula

β = λL/ d => [tex]\frac{(568 *10^{-9})(3.5) }{0.105*10^{-3} }[/tex]

β = 0.019m => 19mm

Therefore, fringe width on the wall will be 19 mm

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