Question 1
What is the molarity of a solution containing 1.2 grams of solute in 450 mL of solution? (
molar mass of solute = 24 g)​

Respuesta :

Answer:

= 0.1 M

Explanation:

450mL = 0.45L

If 24g of a solute are weighed by 1 mole of solute

1.2g of a solute will be weighed by ( 1.2 ÷ 24 )

= 0.05 moles of a solute.

0.45L of a solution are occupied by 0.05 moles

1L will be occupied by ( 1÷0.45 ) × 0.05

= 0.1 M

0.11 M is the molarity of solution containing 1.2 grams of solute in 450 mL of solution.

Molarity

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I Unit of Molarity is molar (M) or mol/L.

How to find molarity of a solution ?

Molarity (M) = [tex]\frac{\text{Mass of solute}}{\text{Molar mass of solute} \times \text{Volume in liter}}[/tex]

From the above definition it is clear that the volume of solution is in liter. In question the volume of solution is given in ml.

So, convert 450 ml into l.

450 ml = [tex]\frac{450}{1000}[/tex] = 0.45 l

Now, put the values in above formula, we get that

Molarity (M) = [tex]\frac{1.2}{24 \times 0.45}[/tex]

                    = [tex]\frac{1.2}{10.8}[/tex]

                    = 0.11 M

Thus, 0.11 M is the molarity of solution containing 1.2 grams of solute in 450 mL of solution.

Learn more about Molarity here: https://brainly.com/question/26873446

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