Determine the stopping location of the prize wheel. At this moment it is centered on the number 13. It is spinning with an energy of 24.38 J. It is slowing at a rate of 1.400 rad/s/s. The disk is made from a wood with a density of 588.0 kg/m^3. The disk is 49.0 mm thick and has a radius of 25.0 cm. Predict the angular displacement it will go through and predict the number on which the wheel will stop. To be safe, you will also get one number the right and to the left of the number you chose. The wheel will spin clockwise. When you are ready to enter your number, hit the end button.

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temmydbrain temmydbrain · Answer 1 · 2020-05-11T04:21:31+02:00

Answer:

Check the explanation

Explanation:

[tex]\omega _{0} = 82\ rad/s[/tex]

[tex]\alpha = - 1.4\ rad/s^{2}[/tex]

[tex]\Theta = ?[/tex]

[tex]\omega _{f} = 0\ rad/s[/tex]

[tex]2*\alpha *\Theta = \omega _{f}^{2}-\omega _{0}^{2}[/tex]

[tex]2*-1.4*\Theta = -82^{2}[/tex]

[tex]\Theta = 2401.429\ radian = 2401.429*\frac{\pi }{180}\ degree = 41.91\ degree[/tex]

Each number in the wheel spans 360/12 = 30 degree

Therefore 41.91 degree corresponds to the number 29 on the wheel when the wheel spins clockwise.