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Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.669 T vertically downward. The electric field is 2.64 x 106 V/m horizontally east. An electron, traveling horizontally northward, experiences zero net force from these fields and so continues moving in a straight line. What is the electron's speed

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okpalawalter8

Answer:

The speed  is [tex]v = 3.946 *10^6 \ m/s[/tex]

Explanation:

From the question we are told that

     The magnetic  field is  [tex]B = 0.669\ T[/tex]

      The electric field is  [tex]E = 2.64 *10^{6} \ V/m[/tex]

     

Generally the speed of the electron is mathematically represented as

               [tex]v = \frac{E}{B}[/tex]

    Substituting values

                [tex]v = \frac{2.64 *10^6}{0.669}[/tex]

                [tex]v = 3.946 *10^6 \ m/s[/tex]

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