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A steam power plant receives heat from a furnace at a rate of 280 GJ/h. Heat transfer to the surrounding air from the steam as it passes through the pipes and other components are estimated to be about 8 GJ/h. If the waste energy is transferred to the cooling water at a rate of 145 GJ/h, determine the (a) net power output and (b) thermal efficiency of this power plan

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Answer:

a) [tex]\dot W = 35.278\,MW[/tex], b) [tex]\eta_{th} = 45.357\,\%[/tex]

Explanation:

a) The net power output of the plant is:

[tex]\dot W = \left(280\,\frac{GJ}{h}-145\,\frac{GJ}{h} - 8\,\frac{GJ}{h} \right)\cdot \left(1000\,\frac{MJ}{GJ} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]

[tex]\dot W = 35.278\,MW[/tex]

b) The thermal efficiency of the power plant is:

[tex]\eta_{th} = \frac{280\,\frac{GJ}{h}-145\,\frac{GJ}{h}-8\,\frac{GJ}{h} }{280\,\frac{GJ}{h} } \times 100\,\%[/tex]

[tex]\eta_{th} = 45.357\,\%[/tex]

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