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In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in 5.0 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.30 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement?

Respuesta :

Chrisnando

Answer:

V = 125.7m/min

Explanation:

Given:

L = 400 mm ≈ 0.4m

D = 150 mm ≈ 0.15m

T = 5 minutes

F = 0.30mm ≈ 0.0003m

To calculate the cutting speed, let's use the formula :

[tex] T = \frac{pi* D * L}{V*F} [/tex]

We are to find the speed, V. Let's make it the subject.

[tex] V = \frac{pi* D * L}{F*T} [/tex]

Substituting values we have:

[tex] V = \frac{pi* 0.4 * 0.15}{0.0003*5} [/tex]

V = 125.68 m/min ≈ 125.7 m/min

Therefore, V = 125.7m/min

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