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As college has ten instructor qualified to teach a special computer lab course that requires two instructors to be present how many different pairs of teachers could there be?

Respuesta :

WorthlessNoises

Answer:

his is like a factorial problem:

7! = 7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040

BUT ... we are looking at only the first two spots. So

7 * 6 = 42

Step-by-step explanation:

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