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A 75.0 mL sample of sulfuric acid (H2SO4) is neutralized by 25.0 mL of 0.150 M NaOH. Calculate the molarity of the sulfuric acid solution.
1. 0.03500 M 2. 0.0500 M 3. 0.450 M 4. 0.0250 M 5. 0.100 M

Respuesta :

Answer:

THE MOLARITY OF SULFURIC ACID SOLUTION IS 0.05 L

Explanation:

Ca Va = Cb Vb

Ca = ?

Va = 75.0mL = 0.075 L

Cb = 0.150 M

Vb = 25.0 mL = 0.025 L

Ca = CbVb/ Va

Ca = 0.150 * 0.025 / 0.075

Ca = 0.00375 / 0.075

Ca = 0.05 M

The molarity is 0.05 L

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