Answer:
option D
Explanation:
Given,
V₁ = 285 L
P₁ = 530 mm Hg
Standard pressure
P₂ = 760 mm Hg
V₂ = ?
Using relation between pressure and volume
[tex]\dfrac{P_1}{V_2}=\dfrac{P_2}{V_1}[/tex]
[tex]\dfrac{530}{V_2}=\dfrac{760}{285}[/tex]
[tex]V_2 = 198.75\ L[/tex]
Hence, volume of the propane at standard pressure is equal to 198.8 L.
Hence, the correct answer is option D.