valkOP
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2. Two trailers, X with mass 500 kg and Y with mass 2000 kg, are being pulled at the same
speed. The ratio of the kinetic energy of Y to that of X is:
A) 1:1
B) 2:1
C) 4:1
D) 9:1
E) 1500:1​

Respuesta :

Chelboy

Answer:C

Explanation:

let the speed be v for both mass x and mass y

mass(x)=500kg

mass(y)=2000kg

Kinetic energy(mass(x))=(500 x v^2)/2

Kinetic energy(mass(x))=250v^2

Kinetic energy(mass(y))=(2000xv^2)/2

Kinetic energy(mass(y))=1000v^2

Ratio of kinetic energy y to x =1000v^2:250v^2

=1000v^2 / 250v^2

=4/1=4:1

Eduard22sly

The correct answer to the question is option C. 4 : 1

Explanation:

Step 1:

Data obtained from the question

Mass of Trailer X (mₓ) = 500 kg

Mass of Trailer Y (mᵧ) = 2000 kg

Let the velocity be 'v'

Ratio of kinetic energy of Y to X =?

Step 2:

Determination of the kinetic energy of Trailer X.

Mass of Trailer X (mₓ) = 500 kg

Velocity = v

Kinetic energy of Trailer X (KEₓ) =?

KEₓ = ½mₓv²

KEₓ = ½ × 500 × v²

KEₓ = 250v²

Step 3:

Determination of the kinetic energy of Trailer Y.

Mass of Trailer Y (mᵧ) = 2000 kg

Velocity = v

Kinetic energy of Trailer Y (KEᵧ) =?

KEᵧ = ½mᵧv²

KEᵧ = ½ × 2000 × v²

KEᵧ = 1000v²

Step 4:

Determination of the ratio of the kinetic energy of Trailer Y to Trailer X.

Kinetic energy of Trailer X (KEₓ) = 250v²

Kinetic energy of Trailer Y (KEᵧ) = 1000v²

Ratio of kinetic energy of Y to X =?

KEᵧ : KEᵧ = 1000v² : 250v²

KEᵧ : KEᵧ = 1000v² / 250v²

KEᵧ : KEᵧ = 4 : 1

Therefore, the ratio of kinetic energy of Trailer Y to Trailer X is 4 : 1

Learn more: https://brainly.com/question/10703928

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