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A 2-kg ball rolls down the hill. By the time it is at the bottom,
the ball's Kinetic Energy is 25 J. What is its velocity at the
bottom of the hill?
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Answer: 5 m/s

Explanation:

v = √ (KE x 2)/(m)

v = √ (25 x 2)/(2)

v = √ (50/2)

v = √25

v = 5 m/s

The velocity at the bottom of the hill will be 5 m/sec. Velocity is a vector quantity. It is a time-based component.

What is velocity?

The change of displacement with respect to time is defined as the velocity.  Velocity at any angle is resolved to get its component of x and y-direction.

Mathematically, the velocity is found as;

[tex]\rm v = \frac{d}{t}[/tex]

The kinetic energy is found as;

[tex]\rm KE = \frac{1}{2} mv^2 \\\\ \rm v= \sqrt{\frac{2KE}{m} } \\\\ v= \sqrt{\frac{2 \times 25}{2} } \\\\ v=\sqrt{25} \\\\ v= 5 m/sec[/tex]

Hence, the velocity at the bottom of the hill will be 5 m/sec.

To learn more about the velocity, refer to the link ;

https://brainly.com/question/862972

#SPJ2

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