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41.6 mL of an HCIO^2 solution were titrated with 14.85 mL of a 0.146 M NaOH solution to reach the equivalence point. What is the Molarity of the HCIO^2 solution. But the 2 s are on the lower right corner

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SvetkaChem

Answer:

0.0521 M

Explanation:

HClO2 + NaOH ---> NaClO2 + H2O

M(HClO2)* V(HClO2) = M(NaOH)*V(NaOH)

M(HClO2)* 41.6 mL = 0.146M*14.85 mL

M(HClO2) = 0.146*14.85/41.6= 0.0521 M

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