contestada

Based on the equation below, how many grams of nitrogen gas (N2) will be produced from the decomposition of one mole of sodium azide (NaN3)? Use a molar mass of 28.0 grams for nitrogen gas (N2).

2NaN3 → 2Na + 3N2
A. 56.0 grams
B. 42.0 grams
C. 28.0 grams
D. 18.7 grams

Respuesta :

Decomposition is a type of reaction in which the reactant or the chemical mixture splits into two or more products. In the given reaction sodium azide decomposes to give nitrogen and sodium.

2 NaN₃ → 2 Na + 3 N₂

The correct answer is:

Option B. 42.0 grams

Given,

  • The molar mass of nitrogen gas = 28 grams

  • Moles of Sodium azide = 1 mole

  • From the given balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

  • As 2 moles of sodium azide decomposes to give 3 moles of nitrogen gas so, 1 mole of sodium azide will decomposes to give 1.5 moles of nitrogen gas.

The number of moles of nitrogen gas produced is 1.5 moles.

To calculate grams of nitrogen gas the formula used will be:

[tex]\text {Molar\;mass (M)} = \dfrac{\text{Mass (m)}}{\text{Moles (n)}}[/tex]

[tex]\text {28} = \dfrac{\text{Mass (m)}}{1.5}}[/tex]

Mass = Molar mass × Moles

= 28 × 1.5

=42 grams.

Therefore, 42 grams of nitrogen gas will be produced from the decomposition of one mole of sodium azide.

To learn more about decomposition reaction follow the given link:

https://brainly.com/question/8009068

Otras preguntas