What is the area, in square feet, of the shaded part of the rectangle below?

Answer:
The area of shaded region is 208 sq.feet
Step-by-step explanation:
Refer the attached figure
ABCD is rectangle
Opposite sides of rectangle are equal so
AB = CD = 16 feet
AD = BC= 17 feet
Area of rectangle = [tex]Length \times Breadth = 16 \times 17 =272 ft^2[/tex]
Now In triangle PCD
CD = 16 feet
PC = BC-BP = 17-9 = 8 feet
Since all angles of rectangle is 90°
So,PCD is a right angles triangle
So, Area of triangle =[tex]\frac{1}{2} \times Base \times Height = \frac{1}{2} \times 16 \times 8 =64 ft^2[/tex]
Area of shaded region = Area of rectangle - Area of triangle = [tex]272-64=208 ft^2[/tex]
Hence The area of shaded region is 208 sq.feet