Answer:
The volume of the piston would be 250 mL.
Explanation:
Volume of the piston, [tex]V_1=500\ mL[/tex]
Pressure, [tex]P_1=15\ atm[/tex]
Let [tex]V_2[/tex] is the volume of piston if the pressure increased to 30.0 atm.
It is based on Boyle's law. It is given by:
[tex]\dfrac{V_1}{V_2}=\dfrac{P_2}{P_1}\\\\V_2=\dfrac{V_1P_1}{P_2}\\\\V_2=\dfrac{500\times 15}{30}\\\\V_2=250\ mL[/tex]
So, the volume of the piston would be 250 mL.
