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Consider the number 4n , where n is a natural number. Check whether there is any value of e N for which 4n ends with the digit zero

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Answer: 25
Explanation: Yes, if we take n=25, then 4n=100, which ends with a zero
Thus, 25 is ONE SUCH value
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ANSWER:

No, [tex] {4}^{n} [/tex] for any value of n cannot end in 0.

STEP-BY-STEP EXPLANATION:

Prime factorisation of 4:

4 = 2 × 2

As seen,

5 is not a prime factor of 4.

Therefore, [tex] {4}^{n} [/tex] for any value of n cannot end in 0.

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