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What is the percent yield for a reaction if the theoretical yield of Fe2(SO4) is 33.14 g and the
actual yield recovered is only 18.5 g? Show your work.

Respuesta :

aabdulsamir

Answer:

% yield = 55.82%

Explanation:

Theoretical yield = 33.14g

Actual yield = 18.5g

Percentage yield = (actual yield / theoretical yield) * 100

%yield = (18.5 / 33.14) * 100

% yield = 0.5582 * 100

% yield = 55.82%

The percentage yield of Fe₂So₄ is 55.82%

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