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Select the statement(s) that explain(s) the relationship between the arrangement of elements by size and first ionization energy.
1. The first set of paired electrons in a pp subshell experience a large amount of electron-electron repulsion, making the fourth electron in a pp subshell easy to remove.
2. The third unpaired electron in a pp subshell causes a lot of electron-electron repulsion among the orbitals, making the third electron in a pp subshell easy to remove.
3. A pp subshell with only one unpaired electron is extremely stable, making the fifth electron in a pp subshell easy to remove.
4. The two arrangements are the same because IE of elements increases from left to right and the radii of elements decreases from left to right.
5. A full ss subshell is able to shield a newly filled pp subshell from the nucleus, making the first electron in a pp subshell easy to remove.

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Answer:

5) A full s subshell is able to shield a newly filled p subshell from the nucleus, making the first electron in a p subshell easy to remove.

Explanation:

Ionization energy reffered to the measurement of the readiness of an atom to lose an electron.

While First ionization energy is defined as the energy required to remove the foremost electron that are held so loosely within the gas phase.

The number of electron in atom proportional to the size of the atom or element.when there are bigger number of electron then their would large size of atom. The ionization energy required to remove primary electron from it's outermost shell decrease as the atom size increase.

Repulsion of Electron to electron takes place when there is repelance between the electrons within the same sub-level. There is shielding effect when inner electrons shield the outer electrons from been pulled off the nuclear charge.

Therefore, a full ss subshell is ready to shield a newly filled p subshell from the nucleus, making the primary electron in an exceedingly p subshell easy to get rid of.

because there is high shielding effect byan s-subshell compare to the p,d, and f sub-shell order, and it is easy to remove new electron within p-sublevel because it is held loosely

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